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To find a step-by-step solution for the distance between two lines. [6] 2019/11/19 09:52 Male / Under 20 years old / High-school/ University/ Grad student / A little / Purpose of use

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    A block of mass m is pushed up against a spring, compressing it a distance x, and is then released. The spring projects the block along a frictionless horizontal surface, giving the block a speed v. The same spring projects a second block of mass 4m, giving it a speed of 3v. What is the distance the spring compressed in the second case?

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    Since the second term on the right side of the equation reduces to 0, the equation can then be simplified to. x = (2.4 m/s)•(0.3499 s) Thus, x = 0.84 m (rounded from 0.8398 m) The answer to the stated problem is that the pool ball is in the air for 0.35 seconds and lands a horizontal distance of 0.84 m from the edge of the pool table.

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    This is shown in the left side of the graph in (c). (b) At some point, the magnitude of the applied force is greater than the force of kinetic friction, and the block moves to the right. This is shown in the right side of the graph. (c) The graph of the frictional force versus the applied force; note that f s (max) > f k. f s (max) > f k.

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    While I realize this is a digression - I have to say that after all my "variable-distance" testing I am beginning to believe that this "good up close but poor-at-distance" claim about the 200-400mm f4 is a huge exaggeration and blown completely out of proportion in its seriousness (and the person - who shall remain nameless here - who first ...

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To find a step-by-step solution for the distance between two lines. [6] 2019/11/19 09:52 Male / Under 20 years old / High-school/ University/ Grad student / A little / Purpose of use